---
title: "How can I calculate the weight of an object in water?"  
description: "How can I calculate the weight of an object in water?"  
author: "Ronan Jone"  
published: 2018-03-09  
canonical: https://answers.mindstick.com/qa/37695/how-can-i-calculate-the-weight-of-an-object-in-water  
category: "science"  
tags: ["gravity"]  
reading_time: 2 minutes  

---

# How can I calculate the weight of an object in water?

How can I calculate the [weight](https://www.mindstick.com/articles/259345/manage-your-weight-with-these-tips-and-tricks) of an object in [water](https://www.mindstick.com/articles/323154/fluoride-in-your-water-filtration-guide-2020)?

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## Answers

### Answer by akriti kashyap

## The weight of an object under Water!

![How can I calculate the weight of an object in water?](https://answers.mindstick.com/questionanswer/0e448f75-7b2e-46f9-916f-099e0571196e/images/fe6bb643-5523-4ffe-99ec-81211ad48a68.png)\

Well, the calculation has always been a trending one in the field of Mathematics and Science as no theory can be proved without a proof…

Here we go providing you with a solution for calculating the **Weight of an Object in the Water!**

The weight of the submerged body of an object can be calculated by subtracting the weight of the volume of water which is been displaced from its air weight.

## Taking into consideration two facts:

- Fresh Water weighs **62.366** pounds/cubic foot
- Saline Water weighs **64.043** pounds/cubic foot

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Hence, the weight of an Object in Water is:

## Ws = Wa – Ww

Where

**Ws:** Submerged Weight of Object

**Wa:** Weight of Object in Air

**Ww:** Weight of Water Displaced

Since Weight can be demonstrated in terms of volume and density. Hence, we substitute the known values of the density…

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## 1. For Fresh Water:

![How can I calculate the weight of an object in water?](https://answers.mindstick.com/questionanswer/0e448f75-7b2e-46f9-916f-099e0571196e/images/a59f7a19-c8ab-4b10-aacc-2f64d7f3a201.png)**\**

**Ws/sea = Wa-(62.366)*Vo** (***Equation 1***)

Where

**Ws/sea:** Submerged Weight of Object in Seawater in pounds

**Wa:** Weight of Object in pounds

**Vo:** Volume of Object in cubic feet

## 2. For Saline Water:

![How can I calculate the weight of an object in water?](https://answers.mindstick.com/questionanswer/0e448f75-7b2e-46f9-916f-099e0571196e/images/e15b2124-9350-40b0-801f-5d6e59d7dedf.png)

**Ws/sea = Wa-(64.0430)*Vo** (***Equation 2***)

Where,

**Ws/sea:** Submerged Weight of Object in Seawater in pounds

**Wa:** Weight of object in pounds

**Vo:** Volume of an object in cubic feet

Now comparing the two **equations, 1 and 2** you can observe that an Object which is submerged in fresh water would lose less of its Air Weight to the **Buoyant Force** of the Fresh Water than the Saline water. Well, the weight of the object would be more when placed in the fresh water. For material with greater density, for example, Lead the difference is of diminutive, wherein one ton of **Lead** would only gain **4 pounds/ton** in a **Fresh Water**. Talking about the concrete **Lead** it would gain **approx. Of 50 pounds/ton** in the **Freshwater**.

## *Experiment more with science and you will gain more!!!*

## Cheers!

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Original Source: https://answers.mindstick.com/qa/37695/how-can-i-calculate-the-weight-of-an-object-in-water

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